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We know that,
Area of parallelogram PQRS = PQ × ST
120 = 15 × ST
ST = 120/15
ST = 8
Now,
In right angled ∆STP
SP² = ST² + PT²
SP² = 8² + 6²
SP² = 64 + 36
SP² = 100
SP = 10
Area of parallelogram PQRS = PQ × ST
120 = 15 × ST
ST = 120/15
ST = 8
Now,
In right angled ∆STP
SP² = ST² + PT²
SP² = 8² + 6²
SP² = 64 + 36
SP² = 100
SP = 10
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