Question

solve this........please​

Answer 1

as we know A=P(1+R/200)n where n is the year I.e. 3/2*2

so it will be.. 18000(1+10/200)3

= 18000*21/20*21/20*21/20

= 20837.25

this is the amount so C.I = A-P = 20837.25-18000= rs.2837.25

Answer 2

Step-by-step explanation:

according to question :-

time = 1.5 yrs

now in question it said that calculated half yearly so dividing the time into 0.5 yrs and 1 yr

P = 18000

Rate = 10%

now in first transaction :-

Amount for half yearly = P (1+r/100)^2

amount = 18000 (1+10/100)^2

amount = 18000(1+1/10)^2 = 18000(11/10)^2

amount = 18000 * 11/10 * 11/10

amount = 180 * 11 * 11 = 21780

now amount for half yearly = 21780

now

amount for 1 yr :-

amount = P(1+r/100)^1 = 18000(1+10/100)^1

amount = 18000(1+1/10)

amount = 18000*11/10 = 1800*11 = 19800

now total amount :-

total amount = amount of half yearly + amount of one year

total amount = 21780 + 19800 = 41580

Now calculating Compound interest for 1.5 yrs :-

CI = amount - principal = 41580 - 18000 = 23580

So Compound Interest = ₹23580

hope you understand plz thank my answer