solve this please and give right answer
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Answer:
iven 5
2x+1
=6×5
x
−1
⟹5
2x
×5=6×5
x
−1
⟹5(5
x
)
2
−6(5
x
)+1=0
put 5
x
=t
⟹5t
2
−6t+1=0
⟹5t
2
−5t−t+1=0
⟹5t(t−1)−(t−1)=0
⟹t=
5
1
,1=5
−1
,5
⟹x=−1,0
Attachments:
Answered by
1
Given 5
2x+1
=6×5
x
−1
⟹5
2x
×5=6×5
x
−1
⟹5(5
x
)
2
−6(5
x
)+1=0
put 5
x
=t
⟹5t
2
−6t+1=0
⟹5t
2
−5t−t+1=0
⟹5t(t−1)−(t−1)=0
⟹t=
5
1
,1=5
−1
,5
0
⟹x=−1,0
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