solve this please as soon as posible
Attachments:
Answers
Answered by
1
2a^2 + 8a - 384
= 2( a^2 + 4a - 192)
= 2 [ a^2 + 16a - 12a - 192]
= 2 [ a(a+16) - 12(a+16)]
= 2 ( a + 16) (a - 12)
= (2)(a+16)(a-12)
= 2( a^2 + 4a - 192)
= 2 [ a^2 + 16a - 12a - 192]
= 2 [ a(a+16) - 12(a+16)]
= 2 ( a + 16) (a - 12)
= (2)(a+16)(a-12)
Answered by
1
2a^2+8a-384=0
divide by 2
a^2+4a-192=0
a^2+(16-12)a-192=0
a^2+16a-12a-192=0
a(a+16)-12(a-16)=0
(a-12)(a+16)=0
a=12 &-16
divide by 2
a^2+4a-192=0
a^2+(16-12)a-192=0
a^2+16a-12a-192=0
a(a+16)-12(a-16)=0
(a-12)(a+16)=0
a=12 &-16
Similar questions