Math, asked by Mayank784, 1 year ago

solve this please as soon as posible

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Answers

Answered by gaurav2013c
1
2a^2 + 8a - 384

= 2( a^2 + 4a - 192)

= 2 [ a^2 + 16a - 12a - 192]

= 2 [ a(a+16) - 12(a+16)]

= 2 ( a + 16) (a - 12)

= (2)(a+16)(a-12)
Answered by rahulbkg93pcs37b
1
2a^2+8a-384=0

divide by 2

a^2+4a-192=0

a^2+(16-12)a-192=0

a^2+16a-12a-192=0

a(a+16)-12(a-16)=0

(a-12)(a+16)=0

a=12 &-16
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