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2) -2 ≤ 1/2 - 2x/3 ≤ 1 5/6
-2 - 1/2 ≤ -2x/3 ≤ 11/6 - 1/2
-5/2 ≤ -2x/3 ≤ 4/3
-15/2 ≤ -2x ≤ 4
-15/4 ≤ -x ≤ 2
15/4 ≥ x ≥ -2
So, x ∈ [-2, 15/4]
3) 7 ≤ -4x + 2 < 12
5 ≤ -4x < 10
-5 ≥ 4x > - 10
-5/4 ≥ x > -5/2
So, x ∈ (-5/2, -5/4]
For graphs just shade the region (the interval) within which the values lie.
If the graph does not touch the points plotted, that is the critical values, then give a hollow circle in that place ( on that point ). Here it will be on the mark -5/2 of Q. no. 3. For 3), shade the region between -5/2 and -5/4 by plotting them on the real no. line. Do similarly in case of 2)
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ok 54 in the answer
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