Math, asked by vedahi10, 9 months ago

solve this please

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Answered by sckbty72
1

Answer:

2) -2 ≤ 1/2 - 2x/3 ≤ 1 5/6

   -2 - 1/2 ≤ -2x/3 ≤ 11/6 - 1/2

   -5/2 ≤ -2x/3 ≤ 4/3

   -15/2 ≤ -2x ≤ 4

   -15/4 ≤ -x ≤ 2

   15/4 ≥ x ≥ -2

   So, x ∈ [-2, 15/4]

3)  7 ≤  -4x + 2 < 12

    5 ≤  -4x < 10

   -5 ≥ 4x > - 10

   -5/4 ≥ x > -5/2

    So, x ∈ (-5/2, -5/4]

For graphs just shade the region (the interval) within which the values lie.

If the graph does not touch the points plotted, that is the critical values, then give a hollow circle in that place ( on that point ). Here it will be on the mark -5/2 of Q. no. 3. For 3), shade the region between -5/2 and -5/4 by plotting them on the real no. line. Do similarly in case of 2)

Answered by rpichawnghlut
0

Answer:

ok 54 in the answer

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