Math, asked by Anonymous, 1 year ago

solve this please it is very urgent.....

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Answered by mysticd
2
I hope this helps you.
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mysticd: :)
Answered by pankaj12je
2
Hey there !!!!!!

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sinθ= 3/5 = opposite side / hypotenuse 

By Pythagores Theorem 

(hypotenuse)² = (adjacent side )² +(opposite side square)²

5² = s² + 3²

25-9=s²

16=s²

s= √16= 4

cosθ = adjacent side / hypotenuse = 4/5

cos∅ = 9/41 = adjacent side / hypotenuse

(hypotenuse)² = (adjacent side)² +(opposite side)²

41² = 9² + x²

1681-81= x²

1600 = x²

x=40

sin∅ = 40/41

So, 

sinθ = 3/5 cosθ=4/5 sin∅ = 40/41 cos∅ = 9/41

cos(θ-∅)=  cosθcos∅+sinθsin∅ =  4*9/41*5 + 40*3/41*5 = 120+36/41*5 

sin(θ-∅) = sinθcos∅-cosθsin∅ = 3*9/41*5 - 4*40/41*5 = 27-160/41*5

cos(θ-∅)/sin(θ-∅) = 156/41*5/-133/41*5 = - 156/133

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Hope this helped you.........



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