solve this please it is very urgent.....
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I hope this helps you.
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mysticd:
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Hey there !!!!!!
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sinθ= 3/5 = opposite side / hypotenuse
By Pythagores Theorem
(hypotenuse)² = (adjacent side )² +(opposite side square)²
5² = s² + 3²
25-9=s²
16=s²
s= √16= 4
cosθ = adjacent side / hypotenuse = 4/5
cos∅ = 9/41 = adjacent side / hypotenuse
(hypotenuse)² = (adjacent side)² +(opposite side)²
41² = 9² + x²
1681-81= x²
1600 = x²
x=40
sin∅ = 40/41
So,
sinθ = 3/5 cosθ=4/5 sin∅ = 40/41 cos∅ = 9/41
cos(θ-∅)= cosθcos∅+sinθsin∅ = 4*9/41*5 + 40*3/41*5 = 120+36/41*5
sin(θ-∅) = sinθcos∅-cosθsin∅ = 3*9/41*5 - 4*40/41*5 = 27-160/41*5
cos(θ-∅)/sin(θ-∅) = 156/41*5/-133/41*5 = - 156/133
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.........
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
sinθ= 3/5 = opposite side / hypotenuse
By Pythagores Theorem
(hypotenuse)² = (adjacent side )² +(opposite side square)²
5² = s² + 3²
25-9=s²
16=s²
s= √16= 4
cosθ = adjacent side / hypotenuse = 4/5
cos∅ = 9/41 = adjacent side / hypotenuse
(hypotenuse)² = (adjacent side)² +(opposite side)²
41² = 9² + x²
1681-81= x²
1600 = x²
x=40
sin∅ = 40/41
So,
sinθ = 3/5 cosθ=4/5 sin∅ = 40/41 cos∅ = 9/41
cos(θ-∅)= cosθcos∅+sinθsin∅ = 4*9/41*5 + 40*3/41*5 = 120+36/41*5
sin(θ-∅) = sinθcos∅-cosθsin∅ = 3*9/41*5 - 4*40/41*5 = 27-160/41*5
cos(θ-∅)/sin(θ-∅) = 156/41*5/-133/41*5 = - 156/133
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.........
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