solve this please picture above it
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The triangle formed will be AOB
The line OA and OB are Perpendicular to each other,
So the points will form a right angled triangle, right angled at O.
Perpendicular = AO = 4 Units
Base = BO = 6 units
Area of triangle = 1/2 Base × Perpendicular
= 4 × 6 / 2
= 4 ×3
= 12 sq. unit.
The line OA and OB are Perpendicular to each other,
So the points will form a right angled triangle, right angled at O.
Perpendicular = AO = 4 Units
Base = BO = 6 units
Area of triangle = 1/2 Base × Perpendicular
= 4 × 6 / 2
= 4 ×3
= 12 sq. unit.
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thanks
wlcm bro :)
Btw coordinate geometry ka triangle ka formula lag sakta h see my answer below
Haa laga sakte hai but ye jyada easy ha
hai*
bhai exam m toh ar of triangle wala method hi lagaye ga na
Bro please mark m brainliest
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Area of triangle OAB = 1/2 { x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ) }
= 1/2 { 0 (0-6) + 4 (6-0) + 0 (0-0) }
= 1/2 (24)
= 12
Hence area of triangle OAB is 12 cm square
= 1/2 { 0 (0-6) + 4 (6-0) + 0 (0-0) }
= 1/2 (24)
= 12
Hence area of triangle OAB is 12 cm square
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