Question

Solve this please ? with explanation !!

Check the attachment for the question .. ​

Answer 1

Step-by-step explanation:

upward turned graph have always a positive

so, a +ve

given f(x) = ax² + bx + c

f(0) = c

at origin graph cut at negative hence

c -ve

as A is -ve

-b/2a is -ve

and a is +ve

b must ve been +ve

it really took me efforts to type all this do mark me brainliest

Answer 2

$\textrm{In a quadratic equation ax ^2 + bx + c :}$

$\longrightarrow\textrm{If a is positive, parabola points upwards in the graph}$

$\longrightarrow\textrm{If a is negative, parabola points downward}$

$\bigstar\textrm{ c is the y-intercept}$

$\longrightarrow\textrm{If c is positive the y-intercept is positive}$

$\longrightarrow\textrm{If c is negative the y-intercept is negative}$

$\textrm{You can find the sign of b from the coordinates of the minimum point on the graph }$$\longrightarrow\textrm{From the graph,since it is an upward parabola, a will be positive}$

$\textrm{Also from the graph,}$ $\textrm{the lowest point is in the IVth quadrant where the x coordinate will be positive}$

$\rm{-b/2a \rightarrow \textrm{ positive }\quad \textrm{, a is also positive}}$

$\rm{-b}/(+i v e) \rightarrow(+i v e)\implies-b \rightarrow(+i v e) \times(+i v e)\implies-b \rightarrow(+i v e)}$

$\rm{Here\: as\: you \: can\: see\: for \: the \: sign \: of\: L H S \: to \: be\: equal\: to \: the\: sign\: of \: R H S\: sign \: of\: b\: must\: be \: negative}$

$\textrm{From the graph y-intercept(the point where the graph cuts the y-axis) is negative}$

$\longrightarrow\textrm{Therefore the sign of c is negative}$

$\textbf{Therefore, Option (B) (+ive) (-ive) (+ive) is the correct answer}$