Solve this please y=5x-8 and y=-6x+3 by elimination.
Answers
Let it be y=5x-8 - ( equation 1 )
let it be y=6x+3 - ( equation 2 )
by elimination process { equation 2 - equation 1 }
y = 5x-8 (-) y=6x+3
( here in the above subtraction we can directly cancel the y because " {y+(-y)} = 0 "
⇒ 5x = 8 (-) 6x = 3
∴ -x = 11
To know the value of x
⇒ y - 6x = 3
( we know the value of x so we will substitute it in the above step )
⇒ y- 6(-11) = 3
⇒ y+66 = 3
⇒ y = 3-66
∴ y = -63
The value of " x = -11 " and " y = -63 "
Hope it helps...
please make brainliest...!
Answer:
y = 5x-8
y = -6x+3
→ 5x-y-8 = 0
-6x-y+3 = 0
→ 5x-y = 8
-6x-y = -3
Using the Elimination method
→ 5x-y = 8×6.............(i)
6x+y = 3×5.............(ii)
Multipaction by eq(i) in 6 and by eq(ii) in 5
30x-6y = 48
30x+5y = 15
- - -
-------------------
-11y = 33
y = 33/-11
y = -3
by put y=-3 in eq(i)
5x-y = 8
5x-(-3) = 8
5x = 8-3
5x = 5
x = 5/5
x = 1
Hence, the value of x and y is 1 and -3 .