solve this plese chapt 12 quadrilateral
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1...by angle sum property of quadrilateral
a+b+c+d=360
100+98+92+d=360
290+d=360
d=70
therefor angle 4 is 70 degree.
2....
let all angles be x then
by angle sum property
x+2x+3x+4x=360
10x=360
x=36
angle 1=x===36
angle 2=2x==72
angle 3=3x==108
angle 4=4x==144
a+b+c+d=360
100+98+92+d=360
290+d=360
d=70
therefor angle 4 is 70 degree.
2....
let all angles be x then
by angle sum property
x+2x+3x+4x=360
10x=360
x=36
angle 1=x===36
angle 2=2x==72
angle 3=3x==108
angle 4=4x==144
strawberry7:
thanks for solving this problem
Answered by
1
hey mate!✌✌
2nd sum: angle A=1x
angle B=2x
angle C=3x
angle D=4x
A + B + C + D =180 DEGREE
1X +2X+3X+4X=180 DEGREE
10X=180 DEGREE
X=180/10
X =18
ANGLE A = 1X = 1×18 =18
ANGLE B= 2X=2×18 =36
angle c =3X =3×18=54
ANGLE D=4X =4×18=72
CHECK THIS ANSWER VERY WELL
& MARK ME AS A BRAINLIST ✌✌
2nd sum: angle A=1x
angle B=2x
angle C=3x
angle D=4x
A + B + C + D =180 DEGREE
1X +2X+3X+4X=180 DEGREE
10X=180 DEGREE
X=180/10
X =18
ANGLE A = 1X = 1×18 =18
ANGLE B= 2X=2×18 =36
angle c =3X =3×18=54
ANGLE D=4X =4×18=72
CHECK THIS ANSWER VERY WELL
& MARK ME AS A BRAINLIST ✌✌
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