Question

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Answer 1

$\sf\huge{\underline{\boxed{Question!}}}$

▶2kg of ice melts when water at 100℃ is poured in a hole drilled in a block of ice. What mass of water is used!?

$\sf\huge{\underline{\boxed{Answer}}}$

Given:

Latent heat of ice, L(m) = $336\times 10^{3}J/kg$

mass of ice, m= 2kg

Similarly,

specific heat of water, S= $4200j/kg/K$

∆T = T1 - T2= 100 - 0 =373 - 273= 100K

let mass of water be m'...

we have both heat energies remains same!

i.e,

Q = $L(w)\times m$==(1)

where 'Q' is heat energy and 'L(m)' as latent heat and 'm' as a mass..

similarly,

Q = $S\times m'$∆T==(2)

since, energies required are same!

hence!

equating!(1)&(2)

$L(w)\times m$ = $S\times m'$∆T

substituting values!

$336\times 10^{3}\times 2= 4200\times m'\times 100$

$672\times 10^{3} = 420\times 10^{3}\times m'$

m' = $\frac{672}{420}$

m' = 1.6kg...

hence , the mass of water poured into an hole in ice block is 1.6kg!!