Math, asked by Anonymous, 10 months ago

solve this plz........​

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Answers

Answered by Anonymous
0

Step-by-step explanation:

do bytp and plus minus

then do factor

then get answer

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Answered by ItzAaryan
0

Hope helps u........

= 1 / (x-1)(x-2) + 1/(x-2)(x-3) = 2/3

= x-3x+x-2/(x-1)(x-2)(x-3) = 2/3

= x^2-3x+x-1/(x-1)(x-2)(x-3) =2/3

= x^-2x-1/(x-1)(x-2)(x-3) =2/3

= x^2-x-x-1/(x-1)(x-2)(x-3) =2/3

= (x-1) (x-2)/(x-1)(x-2)(x-3) =2/3

= x-2/x^2-3x-2x+6 =2/3

= 3x-6 =2x^2-10x+12

= 2x^2-13x+18 =0.......

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