Question

solve this plz anyone........ ​

Answer 1

(39)

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x -2√3=0

⇒4x(√3 x+2) -√3(√3x +2) =0

⇒(√3x +2)(4x -√3) =0

⇒(√3x +2) =0 or (4x-√3) =0

⇒x = -2/√3 or √3/4

(37)

3√5x² +25x +10√5= 0.

3√5x² +15x + 10x +10√5= 0.

3x(√5x + 5) + 2√5(√5x + 5)= 0

(3x +2√5) (√5x + 5) = 0

(3x +2√5) = 0   or  (√5x + 5) = 0

3x = -2√5     or √5x = -5

x = -2√5/3    or x = -5/ √5= -5×√5/√5×√5= -5√5/5= -√5  [by rationalising the denominator]

Hence, roots of equation 3√5x² +25x +10√5= 0 are -2√5/3 and -√5.

(38)

√3x²-2√2x-2√3=0

√3x²-3√2x+√2x=0

√3(x-√6)+√2(x-√6)=0

(√3+√2)(x-√6)=0

=>(√3x+√2)=0. OR. (x-√6)=0

x=-√2/√3. OR. x=√6

Answer 2

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