Question

solve this plzzzz................​

Answer 1

Answer:

$20 \sqrt{2} {m}^{2}$

Step-by-Step Explanation:

a= 15m, b= 6m c=11m

$perimeter = 15 + 6 + 11 = 32m$

$semi \: perimeter = \frac{32}{2} = 16m$

$Area = \sqrt{s(s - a)( s- b)(s -c )}$

$\sqrt{s(s - a)( s- b)( s- c)}$

$\sqrt{16 \times 1 \times 10 \times 5}$

$\sqrt{16 \times 2 \times 5 \times 5}$

$\sqrt{(5 \times 5) \times (4 \times 4) \times 2}$

$5 \times 2 \sqrt{2}$

$20 \sqrt{2} {m}^{2}$

Answer 2

Given :

• a = 15 m
• b = 11 m
• c = 6 m

According to the question :

⟶ s = a + b + c / 2

⟶ s = 15 + 11 + 6 / 2

⟶ s = 32 / 2

⟶ s = 16

To find :

⇝Area of Triangle = $√ s ( s - a ) ( s - b ) ( s - c )$

⟹ $√ 16 ( 16 - 15 ) ( 16 - 11 ) ( 16 - 6 )$

⟹ $√ 16 × 1 × 5 × 10$

⟹ $\bold{20 √2\:m^2}$

$\boxed{So,\:the\:area\:painted\:in\:colour\:=\: \bold{20 √2\:m^2}}$

Formula used :

Area of triangle = $√ s ( s - a ) ( s - b ) ( s - c )$

Extra information :

↪Area of Rectangle = l × b

↪Area of Square = a × a / s × s

↪Area of Parallelogram = b × h

↪Area of Trapezium = ( 1 / 2 ) a + b × h

So, It's Done !!