Question

solve this plzzzz guys fast step by step​

Answer 1

It's too simple dear

Ok

Let me read the question first

Hey your question is really waste

Just apply coulomb's law

But remember that vertices of an equilateral triangle are at a distance of

2/3 l

Where l is length of perpendicular

Now if side of equilateral triangle is a

Then

l = a sin 60 °

= a (root 3)/2

So distance of each vertex is 2/3 l

= 2/3 * a (root 3)/2 = a / (root 3)

Now apply coulomb's law

F = Q * q / (a / root 3)^2

= 3 Q * q / a^2

Now

You must have read or calculated at some point of time in your life that three equal vectors each at an angle 120 ° are canceled out

Same happens here

So net force on Q will be zero

However

Each of the three q will never be in equilibrium but moving apart in symmetry

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