Question

Solve this problem..........​

Answer 1

${( \frac{x + 1}{2} )}^{2} = {( \frac{x - 1}{2} )}^{2} + b {d}^{2} \\ \frac{ {x}^{2} + 2x + 1 }{4} - \frac{ {x}^{2} - 2x + 1}{4} = {bd}^{2} \\ \frac{ {x}^{2} + 2x + 1 - {x}^{2} + 2x - 1}{4} = {bd}^{2} \\ \frac{4x}{4} = {bd}^{2} \\ x = {bd}^{2} \\ \sqrt{x} = bd$