solve this problem 22 nd one. (ch : pair of linear equations in 2 variables)
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Hope it helps..........
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6km -------- Rs 58
10km -------- Rs 90
So for the extra four kilometers(from 6km to 10 km) they are charging Rs 32(Rs 90 - Rs 58)
Hence we can conclude that they are charging Rs 32 for 4 km.... which means for one kilometer they are charging Rs 8.
So obviously they charge Rs 48 for 6 km in terms of charge for a kilometer. But as per the question, they are charging Rs 58, which means they are charging extra Rs 10. This Rs 10 is the fixed charge.
Answer:
Fixed Charge: Rs 10
Charge per Kilometer: Rs 8
The same can also be done by constructing linear equations too..... like taking fixed charge as 'x' and charge per kilometer as 'y'. Then equations would be:
x + 6y = 58
x + 10y = 90
Solve for x and y to get them.
Where x = 10 and y = 8.
10km -------- Rs 90
So for the extra four kilometers(from 6km to 10 km) they are charging Rs 32(Rs 90 - Rs 58)
Hence we can conclude that they are charging Rs 32 for 4 km.... which means for one kilometer they are charging Rs 8.
So obviously they charge Rs 48 for 6 km in terms of charge for a kilometer. But as per the question, they are charging Rs 58, which means they are charging extra Rs 10. This Rs 10 is the fixed charge.
Answer:
Fixed Charge: Rs 10
Charge per Kilometer: Rs 8
The same can also be done by constructing linear equations too..... like taking fixed charge as 'x' and charge per kilometer as 'y'. Then equations would be:
x + 6y = 58
x + 10y = 90
Solve for x and y to get them.
Where x = 10 and y = 8.
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