Question

solve this problem ​

Answer 1

Step-by-step explanation:

x = 11

I HOPE IT MAY HELP YOU

Answer 2

Question

$\sf \large \dfrac{x + 2}{6} - \ \bigg( \dfrac{11 - x}{3} - \dfrac{1}{4} \bigg) = \dfrac{3x - 4}{12}$

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto \large \dfrac{x + 2}{6} - \ \bigg( \dfrac{11 - x}{3} - \dfrac{1}{4} \bigg) = \dfrac{3x - 4}{12}$

$\sf \longmapsto \dfrac{x + 2}{6} - \bigg( \dfrac{4(11 - x) - 3}{12} \bigg) = \dfrac{3x - 4}{12}$

$\sf \longmapsto \dfrac{x + 2}{6} - \bigg( \dfrac{44 - 4x - 3}{12}\bigg ) = \dfrac{3x - 4}{12}$

$\sf \longmapsto \dfrac{x + 2}{6} -\bigg ( \dfrac{ - 4x + 41}{12}\bigg ) = \dfrac{3x - 4}{12}$

$\sf \longmapsto \dfrac{2\bigg(x + 2\bigg) -\bigg ( - 4x + 41\bigg)}{12} = \dfrac{3x - 4}{12}$

$\sf \longmapsto \dfrac{2x + 4 + 4x - 41}{12} = \dfrac{3x - 4}{12}$

Now,12 lies on both sides so it gets automatically cancelled.

$\sf \longmapsto6x - 37 = 3x - 4$

$\sf \longmapsto6x - 3x = - 4 + 37$

$\sf \longmapsto3x = 33$

$\sf \longmapsto \: x = \dfrac{ 33}{3} ={ \bold{ 11}}$

$\sf\large\boxed{ \bold{ \red{x = 11}}}$

Check:-

LHS

$\sf \longmapsto \dfrac{11 + 2}{6} -\bigg ( \dfrac{11 - 11}{3} - \dfrac{1}{4} \bigg)$

$\sf \longmapsto \dfrac{13}{6} - \bigg( - \dfrac{1}{4} \bigg) = \dfrac{13}{6} + \dfrac{1}{4} = \dfrac{26 + 3}{12} = \dfrac{29}{12}$

RHS

$\sf \longmapsto \dfrac{3 \times 11 - 4}{12} = \dfrac{33 - 4}{12} = \dfrac{29}{12}$