Question

Solve this problem (3a+2b) (5a+6b) +(2a_3b)(4a+4b​

Answer 1

Answer:

$3a(5a + 6b) + 2b(5a + 6b) \\ 15 {a}^{2} + 18ab + 10ab + 12 {b}^{2} \\ 15a {}^{2} + 28ab + 12 {b}^{2}$

$2a(4a + 4b) - 3b(4a + 4b) \\ 8 {a}^{2} + 8ab - 12ab + 12b {}^{2} \\ 8 {a}^{2} - 4ab + 12 {b}^{2}$

$15 {a}^{2} + 28ab + 12 {b}^{2} + 8 {a}^{2} - 4ab + 12 {b}^{2}$

$15 {a}^{2} + 8 {a }^{2} + 28ab - 4ab + 12 {b}^{2} + 12b {}^{2}$

$23 {a}^{2} + 24ab + 24 {b}^{2}$