Question

solve this problem
By factorising method
99x^2 - 220 x +99=0
​

Answer 1

Answer:

Plz mark me as the brainliest and thank me if it helped :)

Step-by-step explanation:

99x2−99x=198  

⟹99x2−99x−198=0

⟹99(x2−x−2)=0

For a quadratic equation x2+bx+c=0 and roots α,β we know that b is their sum and c their product, now we have to find two numbers that satisfy α+β=−1 and αβ=−2, by trial and error we find that these numbers are 1 and −2

Knowing that, the equation becomes:

99(x+1)(x−2)=0

⟹x+1=0,x−2=0

⟹x=−1,2

Answer 2

Answer:

Tell which bro please I want to know follow me