Question

solve this problem faster​

Answer 1

Given, u = 20m/s; a = 10 ms^-2

First, let us calculate the maximum distance:

- 2as = v^2 - u^2

or, s = 20m

Hence, half of the distance = 10 m

Now,

$- 2as = {v}^{2} - {u}^{2} \\ = > {v}^{2} = 400 - 200 \\ = > v = 200 \\ = > v = \sqrt{200} = 10 \sqrt{2} m {s}^{ - 1}$

HOPE THIS COULD HELP!!!