Question

solve this problem for the value of x :-

4^(x-1) * (0.5)^(3-2x)=(1/8)^x

Solve this question in a notebook.

Don't SPAM................




​

Answer 1

Answer:

2

)

x−1

×(

2

1

)

3−2x

=(

2

3

1

)

x

(2)^{2x-2}\times (2^{-1})^{3-2x}=2^{-3x}(2)

2x−2

×(2

−1

)

3−2x

=2

−3x

(2)^{2x-2}\times 2^{2x-3}=2^{-3x}(2)

2x−2

×2

2x−3

=2

−3x

(2)^{2x-2+2x-3}=2^{-3x}(2)

2x−2+2x−3

=2

−3x

(2)^{4x-5}=2^{-3x}(2)

4x−5

=2

−3x

(2)^{4x}\times 2^{-5}=2^{-3x}(2)

4x

×2

−5

=2

−3x

\frac{(2)^{4x}}{2^{5}}=2^{-3x}

2

5

(2)

4x

=2

−3x

\frac{(2)^{4x}}{2^{-3x}}=2^{5}

2

−3x

(2)

4x

=2

5

(2)^{4x+3x}=2^{5}(2)

4x+3x

=2

5

(2)^{7x}=2^{5}(2)

7x

=2

5