solve this problem for the value of x :-
4^(x-1) * (0.5)^(3-2x)=(1/8)^x
Solve this question in a notebook.
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0
Answer:
2
)
x−1
×(
2
1
)
3−2x
=(
2
3
1
)
x
(2)^{2x-2}\times (2^{-1})^{3-2x}=2^{-3x}(2)
2x−2
×(2
−1
)
3−2x
=2
−3x
(2)^{2x-2}\times 2^{2x-3}=2^{-3x}(2)
2x−2
×2
2x−3
=2
−3x
(2)^{2x-2+2x-3}=2^{-3x}(2)
2x−2+2x−3
=2
−3x
(2)^{4x-5}=2^{-3x}(2)
4x−5
=2
−3x
(2)^{4x}\times 2^{-5}=2^{-3x}(2)
4x
×2
−5
=2
−3x
\frac{(2)^{4x}}{2^{5}}=2^{-3x}
2
5
(2)
4x
=2
−3x
\frac{(2)^{4x}}{2^{-3x}}=2^{5}
2
−3x
(2)
4x
=2
5
(2)^{4x+3x}=2^{5}(2)
4x+3x
=2
5
(2)^{7x}=2^{5}(2)
7x
=2
5
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