Math, asked by MrNobody78, 4 months ago

solve this problem given above​

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Answered by ItzVenomKingXx
2

\begin{gathered} \boxed { \frac{x}{y} = ( \frac{3}{4} ) {}^{ - 3} \div ( \frac{4}{5} ) {}^{0} } \\ \frac{x}{y} = \frac{4}{3} \div \frac{1}{1 } \\ \frac{x}{y} = \frac{3}{4} \\ \boxed{ \red{ To \: Find \: \: (\frac{x}{y} {})^{ - 2} } = ( \frac{3}{4} ) {}^{ - 2} = (\frac{4}{3} ){}^{2} = \frac{16}{9} }\end{gathered}

Answered by rosoni28
8

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\begin{gathered}\begin{gathered} \boxed { \frac{x}{y} = ( \frac{3}{4} ) {}^{ - 3} \div ( \frac{4}{5} ) {}^{0} } \\ \frac{x}{y} = \frac{4}{3} \div \frac{1}{1 } \\ \frac{x}{y} = \frac{3}{4} \\ \boxed{ \red{ To \: Find \: \: (\frac{x}{y} {})^{ - 2} } = ( \frac{3}{4} ) {}^{ - 2} = (\frac{4}{3} ){}^{2} = \frac{16}{9} }\end{gathered} \end{gathered}

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