Math, asked by TabishFatima786, 1 year ago

solve this problem please

Attachments:

Answers

Answered by soundrarajanksr27
1
P(R+1) - PR=2400
PR+P-PR=2400
P=2400

TabishFatima786: answer is 12000
TabishFatima786: please tell me
soundrarajanksr27: sorry the answer is 1200
soundrarajanksr27: say Sum=P, rate of interest= r,n=2 therefore SI= Pnr/100 i.e2Pr/100. if interest rate increased by 1% SI= 2P(r+1)/100. By given difference b/w the both is 24. i.e 2P(r+1)/100 - 2Pr= 24. or 2P(r+1)- 2Pr= 2400 > 2Pr+2P-2Pr=2400> 2P=2400 > P = 1200.
TabishFatima786: yes
TabishFatima786: your answer is right
TabishFatima786: there is mistake
TabishFatima786: in
TabishFatima786: solution
Answered by nosumittiwari3
11
>h2><center>hello mate</h2></center>

 Answer is Here

 \huge{Solution}:-

Assuming conventional understanding of “rate” being percent return per annum there is not enough information to find a unique answer.

If r is the simple interest rate and S the original sum, your return after two years would be: S[(1+r)^2–1] = Sr^2 + 2Sr

At 1% higher your return would have been: S[(1.01+r)^2–1] = 1.0201 Sr^2 + 1.02Sr

so the difference of 24 rupees would be:

24 = S (0.0201r^2 + 0.02r)

giving you a quadratic:

2.01 Sr^2 + 2Sr - 2400 = 0

If you knew that you started with an investment of, say, 10000 rupees you could solve the quadratic:

20100r^2 + 20000r -2400 = 0

r = [-20,000 +/- sqrt (400,000,000 + 192,960,000)] / 40,200

= 0.1082 or 10.82%

but different starting values of your investment would reveal different interest rates.

→→→→→±±→→→→→±±→→→→→±±→→→→→±±

 <marquee > [tex] HOPE ITS HELP UH!! Okh
Similar questions