Question

solve this problem please please please please please please please!!

Answer 1

SOLUTION:

$( { \frac{5}{7} )}^{2} \div ( { \frac{5}{7} )}^{3x + 1} = { (\frac{5}{7} })^{4} \\ \\ since \: the \: bases \: are \: same \: we \: can \: \\ subtract \: the \: exponents$

So,

${ (\frac{5}{7}) }^{2 + (3x - 1)} = { (\frac{5}{7} )}^{4} \\ \\ again \: the \: bases \: are \: same \: so \: \\ equate \: the \: exponents \: of \: both \\ the \: sides$

2 + (3x - 1) = 4

2 + 3x - 1 = 4

1 + 3x = 4

3x = 4 - 1

3x = 3

x = 3/3

x = 1

Hence, the value of x is 1