Question

solve this problem :root6-root3

Answer 1

√6-√3

√2.√3-√3

√3(√2-1)

Answer 2

Given: Here we have given $\sqrt{6} -\sqrt{3}$

To find: we have to solve the given equation.

Step by step solution:

• Here we have
• we can write 6 as 3×2

        $\sqrt{6} -\sqrt{3}=\sqrt{3}$×$\sqrt{2}-\sqrt{3}$

• we will take common $\sqrt{3}$ from the above equation
• $=\sqrt{3}(\sqrt{2}-1)$

• we can solve upto this as well it is also correct

        Futher expansion:

        we should know these basic values of the given roots to solve it                     further

        $\sqrt{3}=1.732\\\sqrt{2}=1.414$

     $=\sqrt{3}(\sqrt{2}-1)\\=1.732(1.414-1)\\=1.732(0.414)\\=0.7170$

Final answer:

Hence the answer is $\sqrt{3}(\sqrt{2}-1)=0.7170$