Question

Solve this problem with explain

Answer 1

Hello!
Here is your answer

$x ^{2} + x + 1 = 0$
Multiply x on both sides
$x(x {}^{2} + x + 1) = 0 \times x$
$x {}^{3} + x {}^{2} + x = 0$
shifting terms from L. H. S to R. H. S

$x {}^{3} = - x {}^{2} - x$
Adding 1 on both sides
$x {}^{3} + 1 = - x {}^{2} - x + 1$