Question

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A bullet is moving with a speed of 10 m/s hits a wooden plank . The bullet stopped when it penetrated the plank 2cm deep. Calculate the reatardation of the bullet?

Answer 1

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Answer 2

Answer :-

2500 m/s²

Solution :-

Initial velocity ( u ) = 10 m/s

Since the the bullet comes to rest after hitting the wooden plank,

Final velecity ( v ) = 0 m/s

Displace of the bullet = 2 cm = 2 * 1/100 m = 0.02 m

[ Since 1 cm = 1/100 m ]

Let the acceleration of the bullet be 'a' m/s²

Using third eqation of motion

⇒ v² - u² = 2as

⇒ 0² - 10² = 2( a )( 0.02 )

⇒ 0 - 100 = 0.04a

⇒ - 100/0.04 = a

⇒ - 10000/4 = a

⇒ - 2500 = a

⇒ a = - 2500

Retardation = - a = - ( - 2500 ) = 2500 m/s²

Hence, the retardation of the bullet is 2500 m/s².