Question

solve this qs with working​

Answer 1

Answer:

1) a^-6

2) d²e^-4

Explanation:

On multiplication the power of exponents add

On decision the power of exponents substrates

Power of any number 0 = 1

$1) \: \: a { }^{ - 7} \times {a}^{4} \div {a}^{ - 3} \\ = {a}^{ - 7 + 4 - 3} \\ = {a}^{ - 6} = \frac{1}{ {a}^{6} } \\ \\ 2) \: \: (2d) {}^{0} \div (d {}^{2} {e}^{ - 4}) {}^{ - 1} \\ = 1 \times \frac{1}{(d {}^{2} {e}^{ - 4}) {}^{ - 1} } \\ = 1 \times (d {}^{2} {e}^{ - 4}) {}^{ 1} \\ = d {}^{2} {e}^{ - 4}$

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