Question

Solve this quadratic equation:2x/x+3 + 1/2x+3 + 3x+9/(x-3)(2x+3) =0

Answer 1



Sneharika asked in Math

 2x/x-3 + 1/2x+3 + 3x+9/(x-3) (2x+3) = 0 here

(2x / x - 3) + (1 / 2x + 3) + {3x + 9 / (x - 3)(2x + 3)} = 0

-----> {2x(2x + 3) + 1(x - 3) / (x - 3)(2x + 3)} + {3x + 9 / (x - 3)(2x + 3)} = 0

-----> {(4x2 + 6x + x - 3) / (x - 3)(2x + 3)} + {3x + 9 / (x - 3)(2x + 3)} = 0

-----> {4x2 + 7x - 3 / (x - 3)(2x + 3)} + {3x + 9 / (x - 3)(2x + 3)} = 0

-----> (4x2 + 7x - 3 + 3x + 9) / (x - 3)(2x + 3) = 0

-----> 4x2 + 10x + 6 = 0 * (x - 3)(2x + 3)

-----> 4x2 + 10x + 6 = 0

-----> 2x2 + 5x + 3 = 0 

-----> 2x2 + 2x + 3x + 3 = 0

-----> 2x(x + 1) + 3(x + 1) = 0

-----> (2x + 3)(x + 1) = 0

-----> x = - 3 / 2 or -1

-----> x = -1 (ans)        [rejecting - 3 / 2]

Hope this helps !!!!!