Solve this quadratic equation m^2+5m+5=0
Answers
Answered by
2
it can be solved by D method
ie
-b+√d/2a
d=b^2 -4ac
=25-20
=5
first case -5+5/2=0
second case -5-5/2=-5
ie
-b+√d/2a
d=b^2 -4ac
=25-20
=5
first case -5+5/2=0
second case -5-5/2=-5
Answered by
0
m^2+5+0=5m
m^2+5=5m
5m^2=5m
m^2+5=5m
5m^2=5m
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