Solve this quadratic equation root2 xsquare+7x+5root 2=0
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Hey !!
√2 X² + 7X + 5√2 = 0
√2X² + 5X + 2X + 5√2 = 0
X ( √2X + 5 ) + √2 ( √2X + 5 ) = 0
( √2X + 5 ) ( X + √2 ) = 0
( √2X + 5 ) = 0 or ( X + √2 ) = 0
X = -5/√2 or X = - √2.
√2 X² + 7X + 5√2 = 0
√2X² + 5X + 2X + 5√2 = 0
X ( √2X + 5 ) + √2 ( √2X + 5 ) = 0
( √2X + 5 ) ( X + √2 ) = 0
( √2X + 5 ) = 0 or ( X + √2 ) = 0
X = -5/√2 or X = - √2.
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