Question

solve this question?​

Answer 1

Answer:

1. 3

2. 2

3. 1

Explanation:

1. 3×3×3=27

2. (3+2)+(3+2)=10

3. (3+2+2)+(3+1)=11

4. (3+2)+(3)+(3+2+1+1)=15

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Answer 2

Well, This is a simple question;

Let's Suppose three variables for each of the following object we have to find;

Let the cone be x.

Let the white cream be y.

And, Let the pink cream be z.

Now this become easier to say;

First let's have a look in the 1st case;

Here, we have 3 x's that are getting multiplied and giving a value of 27;

Let's write the above situation as an equation;

$x\times x\times x=27$

Simplify;

$x^3=27$

Now we have to take the cube root on both of the sides;

$\sqrt[3]{x^3}=\sqrt[3]{27}$

Simplify;

$x=\bold{3}$

Therefore, we got the value of x as 3.

Now, let's take the other case;

Here these x's are getting added with the y's;

Let's write it as an equation to make it simpler;

$(3+y)+(3+y)=10$

Here, let's remove the parenthesis;

$3+y+3+y=10$

Let's Simplify;

$6+2y=10$

As we have to isolate y, let's subtract 6 from both the sides;

$6+2y-6=10-6$

Simplify;

$2y =4$

Divide 2 from both the sides;

$\dfrac{\cancel{2}y}{\cancel{2}}=\dfrac{4}{2}$

Simplify;

$y=\bold{2}$

Therefore, we got the value of y as 2.

Now let's that the other case;

Here, the equation would be;

$(3+2+2)+(3+z)=11$

Simplify; :)

$(7)+(3+z)=11$

Let's get rid of the parenthesis;

$7+3+z=11$

Simplify;

$10+z=11$

Subtract 10 from both side to isolate z;

$10+z-10=11-10$

Simplify;

$z=\bold{1}$

Therefore, we got the value of z as 1.

Now we can check our value using the other equation;

Here, We are given $(x+y)+(x)+(x+y+z+z)=15$

Let's plug in the values of all the variables;

$(3+2)+(3)+(3+2+1+1)=15$

Simplify;

$(5)+(3)+(7)=15$

Get rid of the parenthesis and add the numbers;

$15=15$

L.H.S = R.H.S.

Therefore, the values of the variables are correct.