Math, asked by Ratan8899, 11 months ago

solve this question....​

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Answered by hereisayushh02
2

ANSWER:

height of well = 8m

radius of well = 21/2m = 10.5m

CSA of cylinder = 2πrh

= (2×8×10.5)m^2

= 168 m^2

cost of plastering = ₹(168 × 20) = 3360

THNKS!

Answered by Anonymous
0

Answer:beautiful answer for beautifull girl

Step-by-step explanation:

inner surface of the well =πrh

d=3.5m,h=10m.

then, inner surface of the well =2*π*3.5/2*10

=110m²

1m²=Rs45

110m²=110*45

=Rs4950.

yr cost hi to find krni thi

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