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Answered by anmolpathak38
4

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Let us assume that √5 is a rational number.

we know that the rational numbers are in the form of p/q form where p,q are co prime

so, √5 = p/q

    p = √5q

we know that 'p' is a rational number. so √5 q must be rational since it equals to p

but it doesn't occurs with √5 since its not an co prime

therefore, p =/= √5q

this contradicts the fact that √5 is an irrational number

hence our assumption is wrong and √5 is an irrational number.

Answered by yuvrajsingh94142
13

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