Question

040
While selling clothes for making flags. a shopkeeper claims to sell each piece of cloth in the shape of an equilateral tri
of each side 10 cm while actually he was selling the same in the shape of an isosceles triangle with sides 10 cm, 10
cm and
8 cm How much cloth was he saving in selling each flag?
14​

Answer 1

step by step explanation:

a=10 cm \\ b=10 cm\\ c=8 cm\\ \frac{a+b+c}{2} = s\\ \\ \frac{10+10+8}{2} \\ \\ \sqrt{S (s-a)(s-b)(s-c)}\\ \sqrt{14 (14-10)(14-10)(14-8)

14 , 4 , 4 and 6 will cut down by simplifying

8\sqrt{21}

8 × 4.58 = 36.64 cm^{2} = Area of isosceles triangle

But the shopkeeper claims to sell the cloth in the shape of an equilateral triangle whose sides are 10 cm each

∴ Area of equilateral triangle = \sqrt{\frac{3}{4} × 10^{2}

25\sqrt{3} = 25 × 1.73

= 43.25 cm ^{2}

hence, the area of the cloth he was saving =

Area of equilateral triangle - area of isosceles triangle

= 43.25 - 36.64

= 6.61 cm^{2}

Answer:6.61 cm^2