Science, asked by singlegirl90222, 1 year ago

Solve this question.... ......​

Attachments:

Answers

Answered by Anonymous
196

\huge\underline{\underline{\bf \orange{Question-}}}

A piece of wire of resistance 20Ω is drawn out so that its lenght is increased to twice of its original lenght . Calculate the resistance of the wire is the new situation .

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Resistance {\sf (R_1)} = 20Ω
  • Lenght = L
  • New Lenght = 2L

\large\underline{\underline{\sf To\:Find:}}

  • New Resistance {\sf (R_2)}

We know that ,

\large{\boxed{\bf \blue{R=\rho\dfrac{L}{A}} }}

\implies{\sf R_1=\dfrac{L}{A} }

\implies{\sf R_2=\dfrac{2L}{\dfrac{A}{2}} }

\implies{\sf R_2=4×\dfrac{L}{A}}

\implies{\sf R_2=4×R_1 }

\implies{\sf R_2=4×20 }

\implies{\bf\red{New\: Resistance ( R_2)=80\:Ω}}

\huge\underline{\underline{\bf \orange{Answer-}}}

New Resistance {\bf \red{80Ω}}

Similar questions