Question

solve this question ​

Answer 1

Answer:

Step-by-step explanation:

cosθ = a/b

base =a hypotenuse = b

P² = H²-B²

P²=b² - a²

$P=\sqrt{b^{2} - a^{2} }$

tanθ = P/B

tanθ    $= \sqrt{b^{2} -a^{2} } /a$

Answer 2

♛HELLO♛

cosθ = adjacent/hypotenuse or a/h --> a/b(given)

tanθ = opposite/adjacent or o/a

o^2 + a^2 = h^2

o = $\sqrt{b^2-a^2}$

tanθ = $\frac{\sqrt{b^2-a^2} }{a}$

therefore option (D)

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