Question

solve this question.

Answer 1

$(v) \: {x}^{2} - 3 = 0\\ \\ {x}^{2} = 3 \\ \\ x = \sqrt{3} \\ \\ the \: zeroes \: are \: + \sqrt{3} \: and \: - \sqrt{3}$

$(VI) S = \frac {-b} {a} \\ \\ And\\ \\ P = \frac {c} {a}$