Question

solve this question ...

Answer 1

Let the number of rupees 50 notes and rupees 100 notes be 'x'and 'y' respectively.

So,
x + y = 50 ..........1
and
50x + 100y = 3000
50 (x + 2y) = 3000
x + 2y = 3000/50
x + 2y = 60.........2

Solving both 1 and 2 by elimination method we get
   x + y  = 50
   x +2y = 60
 (-) (-)      (-)
___________
       -y  = -10
∴ y = 10
Now, substituting y = 10 in eqn 1
x + y = 50
x + 10 = 50
∴  x = 40

∴ There are 40 notes of rupees 50 and 10 notes of rupees 100.

Hope this helps you !!
# Dhruvsh

Answer 2

Let ₹ 50 notes be x and ₹100 notes be y.

50x + 100y = 3000
50( x + 2y) = 3000
x + 2y = 60 -----------(1)

x + y = 50 ----------(2)

subtract equation (2) from(1)

x +2y =60
x + y = 50
- - -
y= 10 x= 40