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Volume of dissolved substance Total volume of liquid×100=percentage
v400×100=15v400×100=15
. So, the equation formed will be-
60+x400+x×100=3260+x400+x×100=32
⇒60+x=0.32(400+x)⇒60+x=0.32(400+x)
⇒60+x=128+0.32x⇒60+x=128+0.32x
⇒0.68x=68⇒0.68x=68
⇒x=100mL⇒x=100mL
Therefore, 100 mL of alcohol should be added to make the strength 32%. This is the required answer.
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