Math, asked by ITZELITEANURAGSHAH, 5 hours ago

SOLVE THIS QUESTION ​

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Answered by bagkakali
1

Answer:

(m^2-n^2)/(m+n)^2×(m^2+mn+n^2)/(m^3-n^3)

=(m+n)×(m-n)×(m^2+mn+n^2)/(m+n)×(m+n)×(m-n)×(m^2+mn+n^2)

=1/(m+n)

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