solve this question..
Attachments:
Answers
Answered by
1
it can be written as sin^-1(2x/1+x^2)
put x=tan theta
sin^-1(2tantheta/1+tan^2theta)
sin^-1(2tantheta/sec^2theta)
sin^-1(2sintheta/costheta ×cos^2theta)
sin^-1(2sinthetacostheta)
sin^-1(sin2theta)
= 2theta
2tan^-1(x) is answer
put x=tan theta
sin^-1(2tantheta/1+tan^2theta)
sin^-1(2tantheta/sec^2theta)
sin^-1(2sintheta/costheta ×cos^2theta)
sin^-1(2sinthetacostheta)
sin^-1(sin2theta)
= 2theta
2tan^-1(x) is answer
kapoor181282p63ys0:
correct and is tan^-1(x)
I don't know
2tan^-1(x) is answer
I don't know
I am confused
check it out
2 tan^-1x is answer
mera b J hi ans but ans book mein ans. tan^-1(x)hai
I don't know I got 2 tan^-1x as answer
okey
Similar questions