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Answered by
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heyyyaaaa HERE is the answer to your question....
<QPR =70° (vertically opposite angle)
By using Angle sum property...
<Q+<P+<R. =180°
60°+70°+<R =180°
130° +<Q=180°
therefore.. <Q =180°-130°. = 50°
HOPE IT WILL HELP YOU????
PLEASE MARK IT AS A BRAINLIEST FRIEND..
PLEASE PRAY FOR KERALA......
THANKS IN ADVANCE ♥♥♥♥♥
<QPR =70° (vertically opposite angle)
By using Angle sum property...
<Q+<P+<R. =180°
60°+70°+<R =180°
130° +<Q=180°
therefore.. <Q =180°-130°. = 50°
HOPE IT WILL HELP YOU????
PLEASE MARK IT AS A BRAINLIEST FRIEND..
PLEASE PRAY FOR KERALA......
THANKS IN ADVANCE ♥♥♥♥♥
armanasj:
I done
Answered by
13
y = 70°[as 70°, y are vertically opposite angles if a line is drawn parallel to QR and passing through point P].
In triangle PQR:
According to angle sum property of a triangle we know that the sum of the angles of a triangle is 180°.
So, 60°+y°+x° = 180°.
Substituting y° with it's value that is 70°:
60°+70°+x° = 180°.
130°+x° = 180°.
Sending 130° to RHS:
x° = 180°-130°.
x° = 50°.
In triangle PQR:
According to angle sum property of a triangle we know that the sum of the angles of a triangle is 180°.
So, 60°+y°+x° = 180°.
Substituting y° with it's value that is 70°:
60°+70°+x° = 180°.
130°+x° = 180°.
Sending 130° to RHS:
x° = 180°-130°.
x° = 50°.
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