Question

solve this question.

Answer 1

Let each side of the triangle be a cm . Then,



Area of the triangle = ( √3/4 × a² ) cm².



Therefore,




√3/4 × a² = 100√3



a² = 400


a = √400


a = 20 cm.



Thus , the length of each side of a ∆ ABC is 20 cm.


Therefore,



Radius of each circle = 10 cm.



Required area = ( Area of ∆ ABC ) - 3 ( Area of a sector with r = 10 cm , ¢ = 60° )



=> ( 100√3 - 3 × 3.14 × 10 × 10 × 60/360 ) cm².



=> { ( 100 × 1.732 ) - 157 } cm².



=> ( 173.2 - 157 ) cm².



=> 16.2 cm².


Hence,


The area of the required part is 16.2 cm².

Answer 2

ana is 919.001010111991