Question

solve this question.

Answer 1

$\textbf{\huge{ANSWER:}}$

The perimeter of any closed figure is the total length of the boundary, covering the figure.

Perimeter of any closed figure can be taken out by adding the length of all the boundaries.

Let the figure be named as given in the picture attached.

By the Pythagoras Theorem, we can find the length of AE and BD:

${6}^{2} + {8}^{2} ={ (Length \: of \: AE \: and \: also \: of\: BD) }^{2} \\ = > 36 + 64 = 100\\ = > \sqrt{100} = 10 \: cm$

AE = BD = 10 cm

In quadrilateral, AEBD:
AB || ED ( As the given figure is a hexagon )
AE = BD
Thus, AB = 12 cm ( As AEBD is ||gm )

Now:

AF + FE + AB + BC + CD + ED

=》 6 + 8 + 12 + 6 + 8 + 12

=》 $\textbf{52 cm}$

Answer: $\textbf{(c) 52 cm}$

Hope it Helps!! :)