Question

solve this question (7+3root5)/(7-3root5)

Answer 1

Hey mate!

Here's ur answer dear:)
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$\frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} } \\ \\ \frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} } \times \frac{7 + 3 \sqrt{5} }{7 + 3 \sqrt{5} } \\ \\ \frac{(7 + 3 \sqrt{5} ) {}^{2} }{(7) {}^{2} - (3 \sqrt{5} ) {}^{2} } \\ \\ \frac{49 + 42\sqrt{5} + 45 }{49 - 45} \\ \\ \frac{188 + 42 \sqrt{5} }{4} \\ \\ \frac{2(94 + 21\sqrt{5}) }{4} \\ \\ \frac{94 + 21 \sqrt{5} }{2}$

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HOPE IT HELPS!

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Answer 2

$\frac{7 + 3\sqrt{5} }{7 - 3 \sqrt{5} }$
AFTER RATIONALISATION
$\frac{49 + 45 + 42 \sqrt{5} }{49 - 45}$
$\frac{94 + 42 \sqrt{5} }{4}$