solve this question​
Attachments:
Answers
Answered by
1
# LHS
(cosecA - sinA) (secA - cosA)
= ( 1/sinA - sinA) ( 1/cosA - cosA)
= [ (1 - sin^2A)/sinA ] [ (1 - cos^2A)/cosA ]
= ( cos^2A / sinA ) ( sin^2A / cosA )
[ sin^2A + cos^2A = 1 ]
= sinA cosA
# RHS
1 / tanA + cotA
= 1 / (sinA/cosA) + (cosA/sinA)
= sinA cosA / (sin^2A + cos^2A)
= sinA cosA
LHS = RHS
Hence Proved
Hope this helps.... plssss make it the brainliest
(cosecA - sinA) (secA - cosA)
= ( 1/sinA - sinA) ( 1/cosA - cosA)
= [ (1 - sin^2A)/sinA ] [ (1 - cos^2A)/cosA ]
= ( cos^2A / sinA ) ( sin^2A / cosA )
[ sin^2A + cos^2A = 1 ]
= sinA cosA
# RHS
1 / tanA + cotA
= 1 / (sinA/cosA) + (cosA/sinA)
= sinA cosA / (sin^2A + cos^2A)
= sinA cosA
LHS = RHS
Hence Proved
Hope this helps.... plssss make it the brainliest
Similar questions
Chemistry,
9 months ago
English,
9 months ago
Social Sciences,
9 months ago
English,
1 year ago
Math,
1 year ago