Math, asked by UtkarshaD, 1 year ago

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Answered by siddhartharao77
1

Answer:

35

Step-by-step explanation:

Length of rectangular garden = 21 m.

Breadth of rectangular garden = 17 m.

Area of rectangular garden = 21 * 17 = 357 m².

Width of the garden = 1.5 m.

Dimensions of the garden leaving the margin:

Length = (21 - 1.5 * 1.5) = 18 m.

Breadth = (17 - 1.5 * 1.5) = 14 m.

Area of the garden leaving the margin = 252 m².

Now,

Area of the margin left for tuberoses = 357 - 252 = 105 m².

Given that 3 tuberoses plants can be planted in 1 m².

Number of tuberoses that can be planted = (105/3) = 35.

Therefore, 35 tuberoses can be planted.

Hope it helps!

Answered by Siddharta7
0

first take the area of garden=21*17= 357 m^2

then the area covered by margins=17*1.5(along width)=25.5

so total area covered by margins along the width is 51.0

area covered by margins along the length=21*1.5=31.5

total area covered along the length=63.0

minus the area of the squares made due to intersecting of lines=1.5*1.5=2.25

thus area to be subtracted=2.25*4=9

total area covered by margins=(63+51)-9=105 m^2

tuberose to be planted=3*105=315

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