Math, asked by 12345512, 11 months ago

solve this question.....​

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Answered by srilakshmi23
1

1)(3^2×4^-3)(3^2×4^3)

(3^2×1/4^3)(3^2×4^3)

3^2×3^2

9×9=81

2)2^-3×4^1=1/2^3×4=4/8=1/2

3)(-2)^4×(-2)^-5+(4)^-1

=(-2)^4×1/(-2)^5+1/4

=-1/2+1/4

=-1/4

4) (3/7)^-6+(3/7)^-6

=(7/3)^6+(7/3)^6

=2(7/3)^6


srilakshmi23: tq for mark
12345512: welcome
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